3a-[2+2(b-a)]=0

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Solution for 3a-[2+2(b-a)]=0 equation:


Simplifying
3a + -1[2 + 2(b + -1a)] = 0

Reorder the terms:
3a + -1[2 + 2(-1a + b)] = 0
3a + -1[2 + (-1a * 2 + b * 2)] = 0
3a + -1[2 + (-2a + 2b)] = 0
3a + [2 * -1 + -2a * -1 + 2b * -1] = 0
3a + [-2 + 2a + -2b] = 0

Reorder the terms:
-2 + 3a + 2a + -2b = 0

Combine like terms: 3a + 2a = 5a
-2 + 5a + -2b = 0

Solving
-2 + 5a + -2b = 0

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '2' to each side of the equation.
-2 + 5a + 2 + -2b = 0 + 2

Reorder the terms:
-2 + 2 + 5a + -2b = 0 + 2

Combine like terms: -2 + 2 = 0
0 + 5a + -2b = 0 + 2
5a + -2b = 0 + 2

Combine like terms: 0 + 2 = 2
5a + -2b = 2

Add '2b' to each side of the equation.
5a + -2b + 2b = 2 + 2b

Combine like terms: -2b + 2b = 0
5a + 0 = 2 + 2b
5a = 2 + 2b

Divide each side by '5'.
a = 0.4 + 0.4b

Simplifying
a = 0.4 + 0.4b

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